A man hold 100 $ n he own to purchsase 100 birsds, egle is@ 5 $, pigen is @ 1 $ n 20 sparrows r simply @ 1 $?

Answers: He could get 9 eagles for $45.00
51 pigens for $51.00
40 sparrows for $2.00
beside $2.00 left over.
This give somebody the third degree can't be solve. You need to grant one more condition! You can't solve 3 variables next to just 2 conditions.

base on your incomplete question, the incomplete solution is

e + p + s = 100 (derived from $100)
5e + p = (1/20)s = 100 (derived from number of birds i.e. 100)
He in recent times has to buy 100 pigeons. That is newly a guess based on an assumption.



P P, you're assuming that the man have to purchase some of each. The asker never said anything in the order of the man having to buy 1 or more of respectively bird.

That's ok... My answer was base on the assumption that the man had to spend exactly $100.00 ...LOL...

You are right give or take a few one thing. It can't be solved near certanty as it sits. Even an incomplete solution cannot be formulated.

Trick question?
How much of that $100.00 does he hold to spend?
Does he have to buy 1 or more of respectively species?

We would need 2 more conditions to solve this.


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